unit:DAY_Sidereal

URI: http://qudt.org/vocab/unit/DAY_Sidereal

Type
Description

The length of time which passes between a given fixed star in the sky crossing a given projected meridian (line of longitude). The sidereal day is \(23 h 56 m 4.1 s\), slightly shorter than the solar day because the Earth 's orbital motion about the Sun means the Earth has to rotate slightly more than one turn with respect to the "fixed" stars in order to reach the same Earth-Sun orientation. Another way of thinking about the difference is that it amounts to \(1/365.2425^{th}\) of a day per day, since even if the Earth did not spin on its axis at all, the Sun would appear to make one rotation around the Earth as the Earth completed a single orbit (which takes one year).

Properties
qudt:iec61360Code
0112/2///62720#UAA412
qudt:symbol
day{sidereal}
Annotations
dcterms:description
The length of time which passes between a given fixed star in the sky crossing a given projected meridian (line of longitude). The sidereal day is \(23 h 56 m 4.1 s\), slightly shorter than the solar day because the Earth 's orbital motion about the Sun means the Earth has to rotate slightly more than one turn with respect to the "fixed" stars in order to reach the same Earth-Sun orientation. Another way of thinking about the difference is that it amounts to \(1/365.2425^{th}\) of a day per day, since even if the Earth did not spin on its axis at all, the Sun would appear to make one rotation around the Earth as the Earth completed a single orbit (which takes one year).
rdfs:label
Sidereal Day(en)
View as:  CSV

Work in progress

RDF/XML
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    xmlns:xsd="http://www.w3.org/2001/XMLSchema#" > 
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    <j.0:symbol>day{sidereal}</j.0:symbol>
    <j.0:informativeReference rdf:datatype="http://www.w3.org/2001/XMLSchema#anyURI">http://en.wikipedia.org/wiki/Sidereal_time</j.0:informativeReference>
    <j.0:hasQuantityKind rdf:resource="http://qudt.org/vocab/quantitykind/Time"/>
    <j.0:informativeReference rdf:datatype="http://www.w3.org/2001/XMLSchema#anyURI">http://scienceworld.wolfram.com/astronomy/SiderealDay.html</j.0:informativeReference>
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    <j.0:conversionMultiplier rdf:datatype="http://www.w3.org/2001/XMLSchema#decimal">86164.099</j.0:conversionMultiplier>
    <j.0:hasDimensionVector rdf:resource="http://qudt.org/vocab/dimensionvector/A0E0L0I0M0H0T1D0"/>
    <j.0:iec61360Code>0112/2///62720#UAA412</j.0:iec61360Code>
    <rdf:type rdf:resource="http://qudt.org/schema/qudt/Unit"/>
    <j.1:description rdf:datatype="http://qudt.org/schema/qudt/LatexString">The length of time which passes between a given fixed star in the sky crossing a given projected meridian (line of longitude). The sidereal day is \(23 h 56 m 4.1 s\), slightly shorter than the solar day because the Earth 's orbital motion about the Sun  means the Earth  has to rotate slightly more than one turn with respect to the "fixed" stars in order to reach the same Earth-Sun orientation. Another way of thinking about the difference is that it amounts to \(1/365.2425^{th}\) of a day per day, since even if the Earth  did not spin on its axis at all, the Sun  would appear to make one rotation around the Earth  as the Earth  completed a single orbit (which takes one year).</j.1:description>
    <rdfs:label xml:lang="en">Sidereal Day</rdfs:label>
  </rdf:Description>
</rdf:RDF>
TURTLE
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<http://qudt.org/vocab/unit/DAY_Sidereal>
  rdf:type <http://qudt.org/schema/qudt/Unit> ;
  <http://purl.org/dc/terms/description> "The length of time which passes between a given fixed star in the sky crossing a given projected meridian (line of longitude). The sidereal day is \\(23 h 56 m 4.1 s\\), slightly shorter than the solar day because the Earth 's orbital motion about the Sun  means the Earth  has to rotate slightly more than one turn with respect to the \"fixed\" stars in order to reach the same Earth-Sun orientation. Another way of thinking about the difference is that it amounts to \\(1/365.2425^{th}\\) of a day per day, since even if the Earth  did not spin on its axis at all, the Sun  would appear to make one rotation around the Earth  as the Earth  completed a single orbit (which takes one year)."^^<http://qudt.org/schema/qudt/LatexString> ;
  <http://qudt.org/schema/qudt/conversionMultiplier> 86164.099 ;
  <http://qudt.org/schema/qudt/hasDimensionVector> <http://qudt.org/vocab/dimensionvector/A0E0L0I0M0H0T1D0> ;
  <http://qudt.org/schema/qudt/hasQuantityKind> <http://qudt.org/vocab/quantitykind/Time> ;
  <http://qudt.org/schema/qudt/iec61360Code> "0112/2///62720#UAA412" ;
  <http://qudt.org/schema/qudt/informativeReference> "http://en.wikipedia.org/wiki/Sidereal_time"^^xsd:anyURI ;
  <http://qudt.org/schema/qudt/informativeReference> "http://scienceworld.wolfram.com/astronomy/SiderealDay.html"^^xsd:anyURI ;
  <http://qudt.org/schema/qudt/symbol> "day{sidereal}" ;
  <http://qudt.org/schema/qudt/ucumCode> "d"^^<http://qudt.org/schema/qudt/UCUMcs> ;
  rdfs:isDefinedBy <http://qudt.org/2.1/vocab/unit> ;
  rdfs:label "Sidereal Day"@en ;
.
JSON
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 ,"uri":"http:\/\/qudt.org\/vocab\/unit\/DAY_Sidereal" 
 ,"properties":["conversion multiplier":"86164.099" 
    ,"description":"The length of time which passes between a given fixed star in the sky crossing a given projected meridian (line of longitude). The sidereal day is \\(23 h 56 m 4.1 s\\), slightly shorter than the solar day because the Earth 's orbital motion about the Sun  means the Earth  has to rotate slightly more than one turn with respect to the \"fixed\" stars in order to reach the same Earth-Sun orientation. Another way of thinking about the difference is that it amounts to \\(1\/365.2425^{th}\\) of a day per day, since even if the Earth  did not spin on its axis at all, the Sun  would appear to make one rotation around the Earth  as the Earth  completed a single orbit (which takes one year)." 
    ,"has dimension vector":"dimension:A0E0L0I0M0H0T1D0" 
    ,"has quantity kind":"quantitykind:Time" 
    ,"iec-61360 code":"0112\/2\/\/\/62720#UAA412" 
    ,"informative reference":"http:\/\/en.wikipedia.org\/wiki\/Sidereal_time" 
    ,"informative reference":"http:\/\/scienceworld.wolfram.com\/astronomy\/SiderealDay.html" 
    ,"isDefinedBy":"&lt;http:\/\/qudt.org\/2.1\/vocab\/unit&gt;" 
    ,"label":"Sidereal Day" 
    ,"symbol":"day{sidereal}" 
    ,"type":"qudt:Unit" 
    ,"ucum code":"d" 
    ]}
JSON-LD
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  "description" : "The length of time which passes between a given fixed star in the sky crossing a given projected meridian (line of longitude). The sidereal day is \\(23 h 56 m 4.1 s\\), slightly shorter than the solar day because the Earth 's orbital motion about the Sun  means the Earth  has to rotate slightly more than one turn with respect to the \"fixed\" stars in order to reach the same Earth-Sun orientation. Another way of thinking about the difference is that it amounts to \\(1/365.2425^{th}\\) of a day per day, since even if the Earth  did not spin on its axis at all, the Sun  would appear to make one rotation around the Earth  as the Earth  completed a single orbit (which takes one year).",
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}

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